YouTipFunction Call Operator Overloading
# C++ Function Call Operator () Overloading
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The function call operator () can be overloaded for class objects. When overloading (), you are not creating a new way to call functions; instead, you are creating an operator function that can take any number of arguments.
The following example demonstrates how to overload the function call operator ().
#include using namespace std; class Distance{ private: int feet; // 0 to infinity int inches; // 0 to 12 public: // Required constructor Distance(){ feet = 0; inches = 0; } Distance(int f, int i){ feet = f; inches = i; } // Overload function call operator Distance operator()(int a, int b, int c) { Distance D; // Perform random calculations D.feet = a + c + 10; D.inches = b + c + 100 ; return D; } // Method to display distance void displayDistance() { cout << "F: " << feet << " I:" << inches << endl; } };int main(){ Distance D1(11, 10), D2; cout << "First Distance : "; D1.displayDistance(); D2 = D1(10, 10, 10); // invoke operator() cout << "Second Distance :"; D2.displayDistance(); return 0;}
When the above code is compiled and executed, it produces the following result:
First Distance : F: 11 I:10Second Distance :F: 30 I:120
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