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# Java Example - Find Specified Element in Array [ Java Example](#) The following example demonstrates how to use the contains() method to find a specified element in an array: ## Main.java File import java.util.ArrayList; public class Main{public static void main(String[]args){ArrayListobjArray = new ArrayList(); ArrayListobjArray2 = new ArrayList(); objArray2.add(0,"common1"); objArray2.add(1,"common2"); objArray2.add(2,"notcommon"); objArray2.add(3,"notcommon1"); objArray.add(0,"common1"); objArray.add(1,"common2"); System.out.println("Elements of objArray："+objArray); System.out.println("Elements of objArray2："+objArray2); System.out.println("Does objArray contain string common2? ： " +objArray.contains("common2")); System.out.println("Does objArray2 contain array objArray? ：" +objArray2.contains(objArray)); }} The output of the above code is: Elements of objArray：[common1, common2] Elements of objArray2：[common1, common2, notcommon, notcommon1] Does objArray contain string common2? ： true Does objArray2 contain array objArray? ： false